Physics-11 : 2: Motion in a Straight Line - Flashcards
1 / 15
What is instantaneous velocity?
Tap to reveal answer
The limit of the average velocity as the time interval \(\Delta t\) becomes infinitesimally small: \( v = \lim_{\Delta t \to 0} \frac{\Delta x}{\Delta t} = \frac{dx}{dt} \).
Flip the card before moving to the next
Thanks — error reported.
View all 15 cards in this deck
| # | Question | Answer |
|---|---|---|
| 1 | What is instantaneous velocity? | The limit of the average velocity as the time interval \(\Delta t\) becomes infinitesimally small: \( v = \lim_{\Delta t \to 0} \frac{\Delta x}{\Delta t} = \frac{dx}{dt} \). |
| 2 | What is average acceleration? | The change of velocity divided by the time interval: \( \bar{a} = \frac{\Delta v}{\Delta t} \). |
| 3 | What is the relation between displacement and time for uniformly accelerated motion? | \( x = v_0 t + \frac{1}{2} a t^2 \). |
| 4 | What is the general kinematic equation relating velocity and displacement when the initial position is \( x_0 \)? | \( v^2 = v_0^2 + 2 a (x - x_0) \). |
| 5 | How does the stopping distance of a vehicle depend on its initial velocity? | It is proportional to the square of the initial velocity. |
| 6 | What does the area under a velocity-time graph between times \( t_1 \) and \( t_2 \) represent? | The displacement of the object during that interval of time. |
| 7 | When is acceleration in the same direction as velocity? | When the particle is speeding up. |
| 8 | Is the magnitude of average velocity always equal to the average speed over the same interval? | No. Average speed is greater than or equal to the magnitude of average velocity. Equality holds only when the particle moves in a straight line without changing direction. |
| 9 | A man walks to a market 2.5 km away at 5 km h⁻¹ and returns at 7.5 km h⁻¹. What is the magnitude of his average velocity for the whole journey? | Zero (displacement is zero). |
| 10 | For the same particle (\( x = a + bt^2 \), \( b = 2.5\,\mathrm{m\,s^{-2}} \)), what is its average velocity between \( t = 2.0\,\mathrm{s} \) and \( t = 4.0\,\mathrm{s} \)? | \( 15\,\mathrm{m\,s^{-1}} \). |
| 11 | How does the curvature of a position-time graph indicate the sign of acceleration? | The graph curves upward for positive acceleration, curves downward for negative acceleration, and is a straight line for zero acceleration. |
| 12 | Before assigning signs to displacement, velocity, and acceleration, what must first be specified? | The origin and the positive direction of the axis — both are a matter of choice. |
| 13 | A man walks to a market 2.5 km away at 5 km h⁻¹ and returns at 7.5 km h⁻¹. What are the magnitude of his average velocity and his average speed over the interval 0 to 30 minutes? | Both are 5 km h⁻¹ (he is still on the outward leg, reaching the market exactly at \( t = 30\,\mathrm{min} \), so path length equals the magnitude of displacement). |
| 14 | A particle's displacement is \( s = t^3 - 6t^2 + 3t + 4 \) (SI units). Using \( v = ds/dt \) and \( a = dv/dt \), what is its velocity at the instant its acceleration is zero? | \( -9\,\mathrm{m\,s^{-1}} \) — acceleration \( a = 6t - 12 \) is zero at \( t = 2\,\mathrm{s} \); velocity there is \( v = 3t^2 - 12t + 3 = -9\,\mathrm{m\,s^{-1}} \). |
| 15 | A particle covers each of three equal parts of a distance at 20 m s⁻¹, 40 m s⁻¹, and 60 m s⁻¹ respectively. What is its average speed for the whole journey? | Approximately 32.7 m s⁻¹ (exactly \( 360/11\,\mathrm{m\,s^{-1}} \)), from total path length divided by total time. |